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nerfdude123
Member Since 19 Feb 2009Offline Last Active Jun 25 2013 11:59 PM
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In Topic: Official Steam/pc Gaming Thread
21 November 2009 - 10:28 PM
Yeah, and in this the end levels of the campaign are actually different from each other. In the previous, you would just sit and wait for the rescue vehicle. In these, you have to do stuff. For example, In the last level of Dead Center you have to go find gas to fill up a car.
In Topic: Official Steam/pc Gaming Thread
21 November 2009 - 10:10 PM
This game is a heck of a lot better than the previous. The melee weapons are absolutely fantastic, the campaigns are a lot more diverse, and there are a lot more guns. I don't think it is worth a buy because of the limited game play, but I definitely recommend renting if you liked the original.
In Topic: I Need Some Major Help!
07 September 2009 - 08:55 PM
Blacksunshine, on Sep 7 2009, 09:52 PM, said:
nerfdude123, on Sep 7 2009, 06:30 PM, said:
No its not correct. the resistor should be on the positive side to limit the power that is being delivered to the LED. on the negative side it does nothing except slow the amount of current that leaves the LED increasing its ability to burst into flames.1337, on Sep 7 2009, 09:16 PM, said:
Switch Resistor (-)-----------| |--------{_}-----------(-) Battery LED (+)-------------------------------------(+)
This is the correct way to wire it, right?
Yes that is correct.
Also the switch being on the negative side also will only hinder the removing power from the LED. switch all that shit around.
Ahh, yes you are correct. I didn't see that it was negative on top. Resistor goes on postitve.
Also can you take a better picture of the switch? The first one is blurry.
In Topic: I Need Some Major Help!
07 September 2009 - 08:45 PM
Noodleownz, on Sep 7 2009, 09:30 PM, said:
After I cut the wire where do the 2 black parts go!?!??! On the Load prongs, or DC IN prongs? I need to know this
Well after rereading that it has four prongs it should go like this
(-)----------(Dc in prong)(Load prong)------(-)
BATTERY................................................LED
(+)---------(DC in prong)(load prong)------(+)
Or so I think. The load is the LED so the load prongs should be connected to it. The DC in is where the power goes.
Again this may not be correct. If it is not try other methods of by a simplier switch.
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